(2y^2-4y+1)-(2y^2+4)=29

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Solution for (2y^2-4y+1)-(2y^2+4)=29 equation: 


Simplifying
(2y2 + -4y + 1) + -1(2y2 + 4) = 29

Reorder the terms:
(1 + -4y + 2y2) + -1(2y2 + 4) = 29

Remove parenthesis around (1 + -4y + 2y2)
1 + -4y + 2y2 + -1(2y2 + 4) = 29

Reorder the terms:
1 + -4y + 2y2 + -1(4 + 2y2) = 29
1 + -4y + 2y2 + (4 * -1 + 2y2 * -1) = 29
1 + -4y + 2y2 + (-4 + -2y2) = 29

Reorder the terms:
1 + -4 + -4y + 2y2 + -2y2 = 29

Combine like terms: 1 + -4 = -3
-3 + -4y + 2y2 + -2y2 = 29

Combine like terms: 2y2 + -2y2 = 0
-3 + -4y + 0 = 29
-3 + -4y = 29

Solving
-3 + -4y = 29

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -4y = 29 + 3

Combine like terms: -3 + 3 = 0
0 + -4y = 29 + 3
-4y = 29 + 3

Combine like terms: 29 + 3 = 32
-4y = 32

Divide each side by '-4'.
y = -8

Simplifying
y = -8

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